Section+2.7

__** Solving Rational Equation s**__ Steps to solving: 1. Factor the denominators 2. Find the lowest common denominator 3. Multiply by the lowest common denominator to remove fractions 4. Solve 5. Check for extraneous solutions.
 * extraneous solutions are solutions that obviously make the equation untrue*

Ex. 2x/(x-1) + 1/(x-3) = 2/(x^2-4x+3) 2x(x-1) + 1/(x-3)= 2/(x-1)(x-3) [2x(x-1) + 1/(x-3)= 2/(x-1)(x-3)] (x-3)(x-1) 2x^2-6x+x-1= 2 2x^2+5x-3=0 (2x+1)(x-3)=0 x= -1/2 or x=3 x=3 is an extraneous solution and when 3 is plugged in for x, the equation is false. {-1/2}

Homework: pg 253 1- odd.